Let, A=B
Then,
AB=BxB
AB-AxA=BxB-AxA
A[B-A]=[B+A][B-A]
A=B+A
Let, A=1
Therefore, Result: 1=2
Then,
AB=BxB
AB-AxA=BxB-AxA
A[B-A]=[B+A][B-A]
A=B+A
Let, A=1
Therefore, Result: 1=2
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